The sum of the squares of three consecutive natural numbers is 110. Find the smallest number.

A5

B6

C7

D8

Explanation

Let numbers be n-1, n, n+1. (n-1)^2 + n^2 + (n+1)^2 = 110 => 3n^2 + 2 = 110 => 3n^2 = 108 => n^2 = 36 => n = 6. Smallest number is n – 1 = 5.

Exam Relevance

Topic: Number System
Subtopic: Consecutive Numbers

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