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What is the total number of prime factors of 2^3 * 3^2 * 5^4?

A3
B7
C9
D24

Explanation

Total prime factors (sum of exponents) = 3 + 2 + 4 = 9.

Exam Relevance
  • Topic: Number System
  • Subtopic: Factors
Submitted by: mcqstutor Team More Mathematics MCQs →

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