The sum of ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. How old is the father now?
A36 years
B38 years
C40 years
D42 years
Explanation
Let father’s age = F and son’s age = S. F + S = 45. Five years ago: (F – 5)(S – 5) = 124. Since S = 45 – F, (F – 5)(40 – F) = 124 => F^2 – 45F + 324 = 0 => (F – 36)(F – 9) = 0. Father’s age is 36 years.
Exam Relevance
- Topic: Averages
- Subtopic: Age Problems

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