The maximum shear stress in a solid circular shaft of diameter ‘d’ subjected to a twisting moment ‘T’ is given by:
A16 T / (pi * d^3)
B32 T / (pi * d^3)
C64 T / (pi * d^4)
D8 T / (pi * d^3)
Explanation
Torsion formula: T / J = tau / r. For a solid circular shaft, polar moment of inertia J = pi*d^4 / 32 and radius r = d / 2. Therefore, tau_max = 16 T / (pi * d^3).

No Comments