Solve for x: log_10(x) + log_10(x – 3) = 1.

A2

B3

C5

D6

Explanation

log_10[x(x – 3)] = 1 => x(x – 3) = 10^1 = 10 => x^2 – 3x – 10 = 0 => (x – 5)(x + 2) = 0. Since log requires positive input, x = 5.

Exam Relevance

Topic: Algebra
Subtopic: Logarithms

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