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In a simultaneous throw of two dice, what is the probability of getting a total of at least 10?

A1/6
B1/9
C5/36
D1/12

Explanation

Favorable outcomes for sum >= 10: Sum 10 (4,6; 5,5; 6,4), Sum 11 (5,6; 6,5), Sum 12 (6,6). Total = 3 + 2 + 1 = 6. Probability = 6 / 36 = 1/6.

Exam Relevance
  • Topic: Probability
  • Subtopic: Two Dice
Submitted by: mcqstutor Team More Mathematics MCQs →

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