In a simultaneous throw of two dice, what is the probability of getting a total of at least 10?
A1/6
B1/9
C5/36
D1/12
Explanation
Favorable outcomes for sum >= 10: Sum 10 (4,6; 5,5; 6,4), Sum 11 (5,6; 6,5), Sum 12 (6,6). Total = 3 + 2 + 1 = 6. Probability = 6 / 36 = 1/6.
Exam Relevance
- Topic: Probability
- Subtopic: Two Dice

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