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In a Boost converter (step-up DC-DC chopper), the average output voltage V_o is given by:

AV_o = D * V_s
BV_o = D * V_s / (1 - D)
CV_o = V_s / (1 - D)
DV_o = (1 - D) * V_s

Explanation

In a Boost converter, output voltage exceeds input voltage and is expressed by V_o = V_s / (1 – D), where D is duty cycle.

Submitted by: mcqstutor Team More Electrical Engineering MCQs →

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