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If (x+y)^2 = 100 and (x-y)^2 = 16, find xy.

A12
B16
C21
D24

Explanation

4xy = (x+y)^2 – (x-y)^2 = 100 – 16 = 84 => xy = 21.

Exam Relevance
  • Topic: Algebra
  • Subtopic: Identities
Submitted by: mcqstutor Team More Mathematics MCQs →

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