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If x – y = 6 and x^2 + y^2 = 116, find the value of xy.

A30
B40
C50
D60

Explanation

(x – y)^2 = x^2 + y^2 – 2xy => 6^2 = 116 – 2xy => 36 = 116 – 2xy => 2xy = 80 => xy = 40.

Exam Relevance
  • Topic: Algebra
  • Subtopic: Identities
Submitted by: mcqstutor Team More Mathematics MCQs →

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