If log_2(x – 1) = 3, find the value of x.
A7
B8
C9
D10
Explanation
log_2(x – 1) = 3 => x – 1 = 2^3 => x – 1 = 8 => x = 9.
Exam Relevance
- Topic: Algebra
- Subtopic: Logarithms
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