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If a polygon has 8 sides (octagon), how many diagonals does it have?

A14
B20
C24
D28

Explanation

Number of diagonals in an n-sided polygon = n(n – 3) / 2 = 8(8 – 3) / 2 = 8 * 5 / 2 = 20.

Exam Relevance
  • Topic: Geometry & Mensuration
  • Subtopic: Diagonals
Submitted by: mcqstutor Team More Mathematics MCQs →

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