If 4x + 3y = 18 and xy = 6, find the value of 16x^2 + 9y^2.

Topic: Algebra
Subtopic: Identities

A180

B184

C188

D192

Explanation

Squaring both sides: (4x + 3y)^2 = 18^2 => 16x^2 + 24xy + 9y^2 = 324 => 16x^2 + 24(6) + 9y^2 = 324 => 16x^2 + 9y^2 = 324 – 144 = 180.

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