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Find the variance of the first 5 natural numbers (1, 2, 3, 4, 5).

A1.5
B2.0
C2.5
D3.0

Explanation

Mean = (1+2+3+4+5)/5 = 3. Squared deviations: (1-3)^2=4, (2-3)^2=1, (3-3)^2=0, (4-3)^2=1, (5-3)^2=4. Sum = 10. Variance = 10 / 5 = 2.0.

Exam Relevance
  • Topic: Statistics
  • Subtopic: Variance
Submitted by: mcqstutor Team More Mathematics MCQs →

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