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Find the smallest square number that is divisible by each of the numbers 6, 9, and 15.

A450
B900
C1600
D3600

Explanation

LCM of 6, 9, 15: 6 = 2*3, 9 = 3^2, 15 = 3*5. LCM = 2 * 3^2 * 5 = 90. To make it a perfect square, multiply by missing prime factors (2 and 5): 90 * 2 * 5 = 900.

Exam Relevance
  • Topic: Number System
  • Subtopic: LCM & Perfect Squares
Submitted by: mcqstutor Team More Mathematics MCQs →

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