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A father is 4 times as old as his son. In 20 years, he will be twice as old as his son. How old is the son now?

A8 years
B10 years
C12 years
D15 years

Explanation

Let son’s age = x, father’s age = 4x. In 20 years: 4x + 20 = 2(x + 20) => 4x + 20 = 2x + 40 => 2x = 20 => x = 10 years.

Exam Relevance
  • Topic: Age Problems, Time & Distance, Work
  • Subtopic: Age Problems
Submitted by: mcqstutor Team More Mathematics MCQs →

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