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If the whole circle bearing (WCB) of a line is 135 degrees 30 minutes, its reduced bearing (RB) is:

AN 44° 30' E
BS 44° 30' E
CS 44° 30' W
DN 44° 30' W

Explanation

A bearing of 135°30′ lies in the second quadrant (SE) between 90° and 180°. Reduced Bearing RB = 180° – 135°30′ = S 44° 30′ E.

Submitted by: mcqstutor Team More Civil Engineering MCQs →

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