In PERT scheduling, the variance ($sigma^2$) of a task duration estimate is mathematically given by:

A$sigma^2 = rac{b - a}{6}$

B$sigma^2 = left(rac{b - a}{6} ight)^2$

C$sigma^2 = rac{b + a}{2}$

D$sigma^2 = (b - m)^2$

Explanation

PERT standard deviation is $sigma = rac{b – a}{6}$, so variance is $sigma^2 = left(rac{b – a}{6}
ight)^2$.

Submitted by: mcqstutor Team More Software Engineering MCQs →