If log_10(2) = 0.3010, what is the value of log_10(80)?

Topic: Algebra
Subtopic: Logarithms

A1.6020

B1.9030

C2.1030

D2.4080

Explanation

log_10(80) = log_10(8 * 10) = log_10(2^3) + log_10(10) = 3 * log_10(2) + 1 = 3(0.3010) + 1 = 0.9030 + 1 = 1.9030.

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