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The sum of a two-digit number and the number formed by reversing its digits is 110. If the digits differ by 4, find the number.

A37
B73
C84
D95

Explanation

Let digits be x and y. 11(x + y) = 110 => x + y = 10. Given |x – y| = 4. Solving x + y = 10 and x – y = 4 gives x = 7, y = 3. Number is 73 (or 37).

Exam Relevance
  • Topic: Number System
  • Subtopic: Digits Problems
Submitted by: mcqstutor Team More Mathematics MCQs →

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