Find the value of x if log_3(x) + log_3(x – 8) = 2.

A7

B8

C9

D10

Explanation

log_3[x(x – 8)] = 2 => x(x – 8) = 3^2 = 9 => x^2 – 8x – 9 = 0 => (x – 9)(x + 1) = 0. Since log requires positive argument, x = 9.

Exam Relevance

Topic: Algebra
Subtopic: Logarithms

Submitted by: mcqstutor Team More Mathematics MCQs →