A bag contains 3 red, 5 green, and 4 blue balls. If two balls are drawn at random together, what is the probability that both are green?
A5/33
B2/11
C5/22
D1/6
Explanation
Favorable ways = C(5, 2) = 10. Total ways = C(12, 2) = 66. Probability = 10 / 66 = 5/33.
Exam Relevance
- Topic: Probability
- Subtopic: Selection

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